найти относительную молекулярную массу:1) H2CO32) CuO3) Na2CO34) CH45) CH3COOH6) Fe2(SO4)3

Mr[H2CO3] = Ar[H] * 2 + Ar[C] + Ar[O] * 3 = 1. 00794 * 2 + 12. 0107 + 15. 9994 * 3 = 62. 02478 = 62

Mr[CuO] = Ar[Cu] + Ar[O] = 63. 546 + 15. 9994 = 79. 5454 = 80

Mr[Na2CO3] = Ar[Na] * 2 + Ar[C] + Ar[O] * 3 = 22. 98976928 * 2 + 12. 0107 + 15. 9994 * 3 = 105. 98843856 = 106

Mr[CH4] = Ar[C] + Ar[H] * 4 = 12. 0107 + 1. 00794 * 4 = 16. 04246 = 16

Mr[CH3COOH] = Ar[C] * 2 + Ar[H] * 4 + Ar[O] * 2 = 12. 0107 * 2 + 1. 00794 * 4 + 15. 9994 * 2 = 60. 05196 = 60

Mr[Fe2(SO4)3] = Ar[Fe] * 2 + Ar[S] * 3 + Ar[O] * 12 = 55. 845 * 2 + 32. 065 * 3 + 15. 9994 * 12 = 399. 8778 = 400