Помомгите написать код на языке PYTHON Спасибо ​

Ваша программа:

import math

x = float(input('Введите аргумент Х точки: '))

if -3 <= x < -1:

y = -x + 1

elif -1 <= x < 1:

y = 0

elif 1 <= x < 5:

y = math. sqrt(4 - (x-3)*(x-3))

elif 5 <= x < 7:

y = -(x/2)+2. 5

else:

print('Х вне допустимого диапазона')

input()

exit()

print('Точка с координатами %2. 2f ; %2. 2f'%(x, y))

А это так, для интереса и наглядности:

import turtle, math

def line(x1,y1,x2,y2):

turtle. pu()

turtle. goto(x1,y1)

turtle. pd()

turtle. goto(x2,y2)

turtle. pu()

turtle. title('График функции')

turtle. setup(800,400)

turtle. setworldcoordinates(-4,-2,8,4)

turtle. hideturtle()

line(-4,0,8,0)

line(0,-2,0,4)

for x in range(-3,8):

line(x,-0. 1, x, 0. 1)

for y in range(-1, 4):

line(-0. 1,y,0. 1,y)

turtle. pensize(2)

line(-3,2,-1,0)

line(-1,0,1,0)

turtle. pd()

x = 1

while x < 5:

turtle. goto(x, math. sqrt(4 - (x-3)*(x-3)))

x += 0. 01

line(5,0,7,-1)

x = float(input('Введите аргумент Х точки: '))

turtle. pencolor('red')

if -3 <= x < -1:

y = -x + 1

elif -1 <= x < 1:

y = 0

elif 1 <= x < 5:

y = math. sqrt(4 - (x-3)*(x-3))

elif 5 <= x < 7:

y = -(x/2)+2. 5

else:

print('Х вне допустимого диапазона')

input()

exit()

y1 = '%2. 2f'%y

print('y = %2. 2f'%y)

turtle. pu()

turtle. goto(x,y)

turtle. dot(7, 'red')

turtle. pensize(1)

turtle. pencolor('green')

line(x,y,0,y)

line(x,y,x,0)

turtle. goto(0. 5,3. 5)

turtle. write('Точка ('+str(x)+'; '+y1+')', font=('Arial',10))

turtle. exitonclick()